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Hcf of 1305 4665 6905

Webdivides 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: a) 4 b) 5 c) 6 d) 8 Asked In TCS shikha (8 years ago) Solved harvinder … Webarithmetic aptitude :: hcf and lcm :: general questions. hcf and lcm - General Questions; hcf and lcm - Important Formulas and Facts ... Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case Then sum of the digits in N is : A) 4. B) 5. C) 6. D) 8. View Answer; Report; Discuss

Let N be the greatest number that will divide …

WebAug 22, 2024 · 6905 - 1305 = 5600. 6905 - 4665 = 2240. 4665 - 1305 = 3360. Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N. = … WebQuestion: Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is . Solution: N = H.C.F. of … daily inspirational quotes for february https://kathrynreeves.com

hcf and lcm arithmetic aptitude Discussion Page Question 61

WebMar 15, 2024 · The HCF and LCM of the two numbers are 13 and 455 respectively. If one of the numbers lies between 75 and 125, then, that numbers are: (a) 78 (b) 91 (c) 104 (d) 117. ... Let N be the greatest number that will divide 1305, 4665, and 6905 leaving the same remainder in each case. Then, the sum of the digits in N is: (a) 4 (b) 5 (c) 6 WebStep 1: Find the prime factors for 40 and 60, The prime factorization of 40 is 2 x 5. The prime factorization of 60 is 2 x 3 x 5. Step 2: List out the highest number of common prime factors of 40 and 60 ie., 2 x 2 x 5. Step 3: Now, on multiplying the common prime factors we will get the HCF of two numbers. 2 * 2 * 5 = 40. WebAug 22, 2024 · If the remainder is same in each case and remainder is not given, HCF of the differences of the numbers is the required greatest number 6905 - 1305 = 5600 6905 - 4665 = 2240 4665 - 1305 = 3360 Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N = HCF of 5600, 2240, 3360 = 1120 Sum of digits in N daily inspirational quotes 2023

If N is the greatest number that will divide 1305, 4665 and 6905 ...

Category:The LCM of the three numbers 45, 25 and 35 is: &n HCF and LCM ...

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Hcf of 1305 4665 6905

Let N be the greatest number that will divide 1305, 4665

Weblet N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. The sum of digits in N is a. 4 b.5 c.6 d.8 Asked In SSC parkv36 (7 years ago) Unsolved Read Solution (2) Is this Puzzle helpful? (6) (1) Submit Your Solution LCM and HCF Advertisements Read Solution (2) : Please Login to Read Solution. WebThe numbers 1305, 4665 and 6905 divided by a four... # HCF AND LCM # HCF AND LCM basic # HCF AND LCM ShortTricks MockoPedia HCF AND LCM PRACTICE Q25 : Q 25.

Hcf of 1305 4665 6905

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WebLet N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: A. 4 B. 5 C. 6 D. 8 Asked In CSC … WebLet N be the greatest number that divides 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: a) 4 b) 5 c) 6 d) 8 Asked In TCS shikha (8 years ago) Solved harvinder Read Solution (2) Is this Puzzle helpful? (12) (3) Submit Your Solution undefined Advertisements Read Solution (2) :

http://placementstudy.com/arithmetic-aptitude/3/hcf-and-lcm/20 WebJun 22, 2024 · Aishwarya06. Since the remainder is same in each case, we will use the following formula-. H.C.F (x, y, z)= H.C.F of (x -y), (y- z), ( z-x) So, let's take out the …

WebA. 4 B. 3 C. 6 D. 5 Solution: If the remainder is same in each case and remainder is not given, HCF of the differences of the numbers is the required greatest number 6905 - 1305 = 5600 6905 - 4665 = 2240 4665 - 1305 = 3360 Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N = HCF of 5600, 2240, 3360 ... WebHighest Common Factor of 4665, 1305, 6905 using Euclid's algorithm. HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily …

WebLet N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. Then, sum of the digits in N is : (1) 4 (2) 5 (3) 6 (4) 8 10. What is the greatest number that will divide 307 and 330 leaving remainder 3 and 7 respectively?

WebUsing Rule 7, The greatest number N = HCF of (1305 – x ), (4665 – x) and (6905 – x), where x is the remainder = HCF of (4665 – 1305), (6905– 4665) and (6905 – 1305) = … bioinformatics university of torontoWebN = H.C.F. of (6905 - 4665), (4665 - 1305), and (6905 - 1305) = H.C.F. of 2240, 3360 and 5600 . HCF of 5600 and 3360: 5600 = 3360 × 1 + 2240 3360 = 2240 × 1 + 1120 2240 = … daily inspection log sheds dobWebThe greatest number N = HCF of (1305 – t ), (4665 – t ) and (6905 – t), where t is the remainder = HCF of (4665 – 1305), (6905– 4665) and (6905 – 1305) = HCF of 3360, … daily inspirational quotes for mondayWebWhat is the HCF of a 2 b 4 + 2 a 2 b 2 and (ab) 7 - 4a 2 b 2? Options A. ab B. a2 b3 C. a2 b2 D. a3 b2 Show Answer Scratch Pad Discuss 7. Find the largest number which divides 1305, 4665 and 6905 leaving same remainder in each case. Also, find the common Remainder. Options A. 1210, 158 B. 1120, 158 C. 1120, 185 D. 1210, 185 Show Answer … daily inspirational quotes for recoveryWeb135 = 3 × 3 × 3 × 5. Find the prime factorization of 405. 405 = 3 × 3 × 3 × 3 × 5. To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 3 × 3 × 3 … bioinformatics university of cincinnatiWebN = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305) = H.C.F. of 3360, 2240 and 5600 = 1120. Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4 Subject: HCF and LCM - Quantitative Aptitude - Arithmetic Ability Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE Job Role: Bank Clerk , Bank PO Related Questions Q: Consider a two-digit number. bioinformatics universities in egyptWebSep 29, 2024 · #HCF AND LCM#HCF AND LCM CONCEPT#HCF#LCM#usefull for all exams#hcf and lcm important questions bioinformatics university of arizona